Robustness

The method also seems quite robust. The cancellation problem when computing $ k_0$ is avoided by using the proper expression. Another cancellation proble occurs while computing $ R-\sqrt{Q^3+ R^2}$ when $ R
\gg Q$. However, this has no consequence as it affects only the $ T$ term which in this case is much smaller than $ S$ and only $ S+T$ is used to compute the solution. As the algorithm converges, all the coefficients also converge ($ k$, $ \alpha$, $ \beta$, $ \gamma$, $ \delta$, $ a_1$, $ a_2$, $ a_3$, $ Q$, $ R$, $ S$, $ T$). There is no numerical explosion anywhere.



Luc Maisonobe 2006-02-04